It takes 3 moles of H2O to produce 1 mole of Fe2O3
so, since you have 1.24 moles of H20, you will get 0.413 moles of Fe2O3.
So, how many grams is that?
2Fe+3H2O→Fe2O3+3H2
If 1.24 mol of water react, how many g of iron(III) oxide would be produced?
I know that the answer to this is 66.0 g but I don't understand how to solve it.
4 answers
I'm sorry, I don't understand the next step.
mols = grams/molar mass. You have mols and you can calculate molar mass; substitute and solve for grams.
Fe2O3 has 2 atoms of Fe (55.845 g/mol)
and 3 atoms of O (16g/mol)
so, a mole of Fe2O3 is 2*55.845 + 3*16 = 159.69 grams
You have only 0.413 moles = 0.413 * 159.69 = 65.95 grams
or 66.0 if you round to the nearest 0.1 gram.
and 3 atoms of O (16g/mol)
so, a mole of Fe2O3 is 2*55.845 + 3*16 = 159.69 grams
You have only 0.413 moles = 0.413 * 159.69 = 65.95 grams
or 66.0 if you round to the nearest 0.1 gram.
2 answers