Asked by david
2e^(4x^2)=3
how do i solve for x. do i use the ln methode because i don't know how to do that. by calculator, i got x=.168 but i don't know how to show my work. please help me solve for x.
Take natural logs of both sides.
ln 2 + 4 x^2 = ln 3
4 x^2 = ln (3/2) = 0.40547
x^2 = 0.10137
x = (+ or -) 0.31838...
5x-12=2x-21
how do i solve for x. do i use the ln methode because i don't know how to do that. by calculator, i got x=.168 but i don't know how to show my work. please help me solve for x.
Take natural logs of both sides.
ln 2 + 4 x^2 = ln 3
4 x^2 = ln (3/2) = 0.40547
x^2 = 0.10137
x = (+ or -) 0.31838...
5x-12=2x-21
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