5 mol CH3OH x (3 mols O2/2 mol CH3OH) = 5*3/2 = ? mols O2.
grams O2, if you need it = mols O2 x molar mass O2.
2CH3OH + 3O2-> 2CO2 + 4 H2O
wHAT IS THE AMOUNT OF OXYGEN IS REQUIRED TO COMPLETRLY BURN 5 MOL OF METHANOL?
1 answer