2C2H6 + 7O2 yields 4CO2 + 6H2O
What is the (∆rH°) of this equation?
2 answers
I think I was able to calculate 3119.656 KJ, but is that correct?
Let's put it this way. I don't want to find my tables, look up the values, find my calculator, plug in the numbers and type in those numbers. However, if you used
dHo rxn = ((n*dHo products) - (n*dH reactants) your answer should be good.
dHo rxn = ((n*dHo products) - (n*dH reactants) your answer should be good.
2 answers