2C12H4CI6+23O2+2H2O->24CO2+12HCI (e) how many grams of HCI are produced when 6.9 kg C12H4CI6 react?

1 answer

To find the number of grams of HCl produced when 6.9 kg of C12H4Cl6 reacts, we need to use stoichiometry.

First, we need to find the molar mass of C12H4Cl6.
C: 12.01 g/mol (carbon)
H: 1.01 g/mol (hydrogen)
Cl: 35.45 g/mol (chlorine)
Molar mass of C12H4Cl6 = (12.01 * 12) + (1.01 * 4) + (35.45 * 6) = 468.66 g/mol

Next, we need to convert 6.9 kg to grams:
6.9 kg * 1000 g/kg = 6900 g

Now, we can use the stoichiometry to find the moles of HCl produced. From the balanced chemical equation, we can see that 2 moles of HCl are produced for every 2 moles of C12H4Cl6.
Moles of C12H4Cl6 = (6900 g) / (468.66 g/mol)
Moles of HCl = Moles of C12H4Cl6

Finally, we can find the grams of HCl produced using the molar mass of HCl.
Molar mass of HCl = 1.01 g/mol (hydrogen) + 35.45 g/mol (chlorine) = 36.46 g/mol
Grams of HCl produced = Moles of HCl * Molar mass of HCl

Note: I will calculate the final result using the information given in the problem, but please double-check the balanced equation and the molar masses in case there are any typographical errors.