2C12H4CI6+23O2+2H2O->24CO2+12HCI (a) how many moles of water are needed to react with 12.8 mol O2?

Answer 1

From the balanced chemical equation, we can see that 23 moles of O2 react with 2 moles of water.

To find out how many moles of water are needed to react with 12.8 moles of O2, we can set up a proportion:

(23 moles O2) / (2 moles H2O) = (12.8 moles O2) / (x moles H2O)

Cross multiplying gives us:

23 moles O2 * x moles H2O = 2 moles H2O * 12.8 moles O2

23x = 25.6

Divide both sides of the equation by 23 to solve for x:

x = 25.6 / 23

x = 1.113 moles H2O

Therefore, 1.113 moles of water are needed to react with 12.8 moles of O2.