2ax -4bx+2by factorise completely

Answer 1

To factorize 2ax - 4bx + 2by completely, we can first factor out the common factor of 2:

2ax - 4bx + 2by = 2(a-b)y - 2bx

Next, we can factor out the common factor of -2b:

2(a-b)y - 2bx = -2b(x - (a-b)y)

Therefore, the complete factorization of 2ax - 4bx + 2by is:

2ax - 4bx + 2by = -2b(x - (a-b)y)