2al + 3fe^(3+) → 2al^(3+) + 3fe

convert to the correct oxidation half-reaction

A: Al^(3+) + 3e^(-) → Al
B: Fe^(3+) + 3e^(-) → Fe
C: Al → Al^(3+) + 3e
D: Fe → Fe^(3+) + 3e^(-)

1 answer

To convert the given redox reaction into the correct oxidation half-reaction, we need to identify which species is being oxidized.

In the reaction:

\[ 2 \text{Al} + 3 \text{Fe}^{3+} \rightarrow 2 \text{Al}^{3+} + 3 \text{Fe} \]

Aluminum (Al) is oxidized from its elemental form (0 oxidation state) to aluminum ions (\( \text{Al}^{3+} \)), while iron (\( \text{Fe}^{3+} \)) is reduced to elemental iron (Fe).

The oxidation half-reaction involves the loss of electrons. For aluminum, this is expressed as:

\[ \text{Al} \rightarrow \text{Al}^{3+} + 3e^- \]

This corresponds to option C:

C: Al → Al^(3+) + 3e

Thus, the correct oxidation half-reaction is C.

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