2Al + 3CuSO4 --> + 3Cu + Al2(SO4)3

Question

* copper(II) sulphate is a hydrate

1.2g of CuSo4
50mL of water
1.0 g of aluminum foil

What is the limiting reactant?

Answer 1

2Al + 3CuSO4.5H2O ==>3Cu + Al2(SO4)3 + 5H2O

Convert g Al to moles.
Convert g CuSO4.5H2O to moles.

Using the coefficients in the balanced equation convert moles Al and moles CuSO4.5H2O (in separate operations) to moles of any product. The reagent producing the SMALLER moles will be the limiting reagent (and that is always true). .

Answer 2

So the limiting reactant is aluminum?
Thank you so much!

Answer 3

oh wait. no. the limiting reactant is CuSO4

Answer 4

CuSO4.5H2O is the limiting reagent. Right the second time. And I have used CuSO4.5H2O since your first post indicated it was a hydrate. If it actually is a hydrate you should show it as a hydrate when you write it out.