Question
An amount was deposited into an account paying interest of 14% per annum effective for 22 months compounded monthly. At the end of the period the account was worth R20 000. What was the amount deposited?
Answers
GPT 3.5
To find the amount deposited, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = the amount in the account at the end of the period (R20 000)
P = the principal amount (the amount deposited)
r = annual interest rate (14% or 0.14)
n = number of times the interest is compounded per year (12 since it is compounded monthly)
t = time the money is invested for (22/12 years)
Substitute the given values into the formula:
20,000 = P(1 + 0.14/12)^(12*(22/12))
20,000 = P(1 + 0.01166666667)^22
20,000 = P(1.01166666667)^22
20,000 = P(1.282159)
Divide both sides by 1.282159:
P = 20,000 / 1.282159
P ≈ R15,581.53
Therefore, the amount deposited was approximately R15,581.53.
A = P(1 + r/n)^(nt)
Where:
A = the amount in the account at the end of the period (R20 000)
P = the principal amount (the amount deposited)
r = annual interest rate (14% or 0.14)
n = number of times the interest is compounded per year (12 since it is compounded monthly)
t = time the money is invested for (22/12 years)
Substitute the given values into the formula:
20,000 = P(1 + 0.14/12)^(12*(22/12))
20,000 = P(1 + 0.01166666667)^22
20,000 = P(1.01166666667)^22
20,000 = P(1.282159)
Divide both sides by 1.282159:
P = 20,000 / 1.282159
P ≈ R15,581.53
Therefore, the amount deposited was approximately R15,581.53.
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