Solv log10(6) + log10(45)-Log10(27)

Answer 1

log10(6) + log10(45) - log10(27)

Using the properties of logarithms:
log(a) + log(b) = log(a*b)
log(a) - log(b) = log(a/b)

log10(6) + log10(45) - log10(27) = log10(6*45) - log10(27)
= log10(270) - log10(27)
= log10(270/27)
= log10(10)
= 1

So, log10(6) + log10(45) - log10(27) = 1.