To find the value of N such that the expression X^2 + 11X + N is a perfect square trinomial, we need to complete the square.
The general form of a perfect square trinomial is (X + A)^2 = X^2 + 2AX + A^2
In this case, we have X^2 + 11X + N
To make this expression a perfect square trinomial, we need to find the value of N such that 2A = 11 and A^2 = N.
From 2A = 11, we have A = 11/2 = 5.5
Therefore, N = A^2 = (5.5)^2 = 30.25
So, the value of N so that the expression X^2 + 11X + N is a perfect square trinomial is 30.25.
What is the value of N so that the expression X squared +11 X plus N is a perfect square trinomial
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