Asked by Ken
Kp for the reaction CaCO3 <---> CaO + CO2 at 350 degrees C is 0.105. Kc for the reaction at the same temp is _____.
This is what I did. I changed all the moles into M. Then I subbed everything into the Kc formula and then changed it into a quadratic. Then everything looked wrong, and I started getting confused.
This is what I did. I changed all the moles into M. Then I subbed everything into the Kc formula and then changed it into a quadratic. Then everything looked wrong, and I started getting confused.
Answers
Answered by
Ken
No, looking at wrong page in homework, on this problem, I subbed everything into the Kp=Kc(RT)delta n, and then tried to isloate Kc, but I don't think I am right
Answered by
DrBob222
Kc = Kp(RT)^-delta n.
You know Kp, R = 0.082 and T = 273 + 350. Delta n is n products - n reactants and for the GASEOUS equation, n products is 1 and n reactants = 0
You know Kp, R = 0.082 and T = 273 + 350. Delta n is n products - n reactants and for the GASEOUS equation, n products is 1 and n reactants = 0
Answered by
DrBob222
Don't change to molarities for these problems. n refers to the number of mols in the balanced equation, not the number of mol in the reaction vessel.
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