Solve. sqrt of b^4/25=4

1 answer

To solve this equation, we need to isolate the variable b on one side of the equation.

First, square both sides of the equation to get rid of the square root.

(b^4/25) = 4^2
b^4/25 = 16

Next, multiply both sides by 25 to get rid of the denominator:

b^4 = 16*25
b^4 = 400

Then, take the fourth root of both sides to solve for b:

b = ±√400
b = ±20

Therefore, the solutions to the equation are b = 20 or b = -20.
Similar Questions
  1. When I solve the inquality 2x^2 - 6 < 0,I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or
    1. answers icon 0 answers
    1. answers icon 2 answers
  2. Solve in the exact form.(sqrt of 4x+1)+(sqrt of x+1)=2 Someone showed me to do this next: Square both sides..so.. 4x+1+2((sqrt
    1. answers icon 4 answers
  3. Could someone show me how to solve these problems step by step....I am confused on how to fully break this down to simpliest
    1. answers icon 1 answer
more similar questions