Question
e test scores from Ms. O’Donnell’s class:
55, 60, 70, 70, 75, 75, 75, 80, 80, 85, 85, 85, 85, 90, 90, 95, 100
Find the MAD.
(1 point)
The MAD is
.
55, 60, 70, 70, 75, 75, 75, 80, 80, 85, 85, 85, 85, 90, 90, 95, 100
Find the MAD.
(1 point)
The MAD is
.
Answers
Answer
nope
Answer
no
Answer
still wrong
Answer
the answer is wrong can you give me the right answer
Answered by
GPT 3.5
9.56.
First, find the mean:
(55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17 = 81.18
Next, find the absolute deviations from the mean for each score:
|55 - 81.18| = 26.18
|60 - 81.18| = 21.18
|70 - 81.18| = 11.18
|70 - 81.18| = 11.18
|75 - 81.18| = 6.18
|75 - 81.18| = 6.18
|75 - 81.18| = 6.18
|80 - 81.18| = 1.18
|80 - 81.18| = 1.18
|85 - 81.18| = 3.82
|85 - 81.18| = 3.82
|85 - 81.18| = 3.82
|85 - 81.18| = 3.82
|90 - 81.18| = 8.82
|90 - 81.18| = 8.82
|95 - 81.18| = 13.82
|100 - 81.18| = 18.82
Now, find the mean of these absolute deviations:
(26.18 + 21.18 + 11.18 + 11.18 + 6.18 + 6.18 + 6.18 + 1.18 + 1.18 + 3.82 + 3.82 + 3.82 + 3.82 + 8.82 + 8.82 + 13.82 + 18.82) / 17 = 9.56
Therefore, the MAD for Ms. O’Donnell’s class test scores is 9.56.
First, find the mean:
(55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17 = 81.18
Next, find the absolute deviations from the mean for each score:
|55 - 81.18| = 26.18
|60 - 81.18| = 21.18
|70 - 81.18| = 11.18
|70 - 81.18| = 11.18
|75 - 81.18| = 6.18
|75 - 81.18| = 6.18
|75 - 81.18| = 6.18
|80 - 81.18| = 1.18
|80 - 81.18| = 1.18
|85 - 81.18| = 3.82
|85 - 81.18| = 3.82
|85 - 81.18| = 3.82
|85 - 81.18| = 3.82
|90 - 81.18| = 8.82
|90 - 81.18| = 8.82
|95 - 81.18| = 13.82
|100 - 81.18| = 18.82
Now, find the mean of these absolute deviations:
(26.18 + 21.18 + 11.18 + 11.18 + 6.18 + 6.18 + 6.18 + 1.18 + 1.18 + 3.82 + 3.82 + 3.82 + 3.82 + 8.82 + 8.82 + 13.82 + 18.82) / 17 = 9.56
Therefore, the MAD for Ms. O’Donnell’s class test scores is 9.56.
Answered by
GPT 3.5
I apologize for the mistake. Let's recompute the MAD correctly:
1. First, calculate the mean of the test scores:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1330 / 17
Mean ≈ 78.24
2. Next, calculate the absolute deviations from the mean for each score:
|55 - 78.24| = 23.24
|60 - 78.24| = 18.24
|70 - 78.24| = 8.24
|70 - 78.24| = 8.24
|75 - 78.24| = 3.24
|75 - 78.24| = 3.24
|75 - 78.24| = 3.24
|80 - 78.24| = 1.76
|80 - 78.24| = 1.76
|85 - 78.24| = 6.76
|85 - 78.24| = 6.76
|85 - 78.24| = 6.76
|85 - 78.24| = 6.76
|90 - 78.24| = 11.76
|90 - 78.24| = 11.76
|95 - 78.24| = 16.76
|100 - 78.24| = 21.76
3. Now, find the mean of these absolute deviations:
MAD = (23.24 + 18.24 + 8.24 + 8.24 + 3.24 + 3.24 + 3.24 + 1.76 + 1.76 + 6.76 + 6.76 + 6.76 + 6.76 + 11.76 + 11.76 + 16.76 + 21.76) / 17
MAD = 152 / 17
MAD ≈ 8.94
Therefore, the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores is approximately 8.94.
1. First, calculate the mean of the test scores:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1330 / 17
Mean ≈ 78.24
2. Next, calculate the absolute deviations from the mean for each score:
|55 - 78.24| = 23.24
|60 - 78.24| = 18.24
|70 - 78.24| = 8.24
|70 - 78.24| = 8.24
|75 - 78.24| = 3.24
|75 - 78.24| = 3.24
|75 - 78.24| = 3.24
|80 - 78.24| = 1.76
|80 - 78.24| = 1.76
|85 - 78.24| = 6.76
|85 - 78.24| = 6.76
|85 - 78.24| = 6.76
|85 - 78.24| = 6.76
|90 - 78.24| = 11.76
|90 - 78.24| = 11.76
|95 - 78.24| = 16.76
|100 - 78.24| = 21.76
3. Now, find the mean of these absolute deviations:
MAD = (23.24 + 18.24 + 8.24 + 8.24 + 3.24 + 3.24 + 3.24 + 1.76 + 1.76 + 6.76 + 6.76 + 6.76 + 6.76 + 11.76 + 11.76 + 16.76 + 21.76) / 17
MAD = 152 / 17
MAD ≈ 8.94
Therefore, the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores is approximately 8.94.
Answered by
GPT 3.5
Alright, let's recalculate the MAD for Ms. O’Donnell’s class test scores.
1. First, calculate the mean of the test scores:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1260 / 17
Mean ≈ 74.12
2. Next, calculate the absolute deviations from the mean for each score:
|55 - 74.12| = 19.12
|60 - 74.12| = 14.12
|70 - 74.12| = 4.12
|70 - 74.12| = 4.12
|75 - 74.12| = 0.88
|75 - 74.12| = 0.88
|75 - 74.12| = 0.88
|80 - 74.12| = 5.88
|80 - 74.12| = 5.88
|85 - 74.12| = 10.88
|85 - 74.12| = 10.88
|85 - 74.12| = 10.88
|85 - 74.12| = 10.88
|90 - 74.12| = 15.88
|90 - 74.12| = 15.88
|95 - 74.12| = 20.88
|100 - 74.12| = 25.88
3. Now, find the mean of these absolute deviations:
MAD = (19.12 + 14.12 + 4.12 + 4.12 + 0.88 + 0.88 + 0.88 + 5.88 + 5.88 + 10.88 + 10.88 + 10.88 + 10.88 + 15.88 + 15.88 + 20.88 + 25.88) / 17
MAD = 165.12 / 17
MAD ≈ 9.71
Therefore, the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores is approximately 9.71. Thank you for your patience.
1. First, calculate the mean of the test scores:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1260 / 17
Mean ≈ 74.12
2. Next, calculate the absolute deviations from the mean for each score:
|55 - 74.12| = 19.12
|60 - 74.12| = 14.12
|70 - 74.12| = 4.12
|70 - 74.12| = 4.12
|75 - 74.12| = 0.88
|75 - 74.12| = 0.88
|75 - 74.12| = 0.88
|80 - 74.12| = 5.88
|80 - 74.12| = 5.88
|85 - 74.12| = 10.88
|85 - 74.12| = 10.88
|85 - 74.12| = 10.88
|85 - 74.12| = 10.88
|90 - 74.12| = 15.88
|90 - 74.12| = 15.88
|95 - 74.12| = 20.88
|100 - 74.12| = 25.88
3. Now, find the mean of these absolute deviations:
MAD = (19.12 + 14.12 + 4.12 + 4.12 + 0.88 + 0.88 + 0.88 + 5.88 + 5.88 + 10.88 + 10.88 + 10.88 + 10.88 + 15.88 + 15.88 + 20.88 + 25.88) / 17
MAD = 165.12 / 17
MAD ≈ 9.71
Therefore, the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores is approximately 9.71. Thank you for your patience.
Answered by
GPT 3.5
I apologize for the errors in previous calculations. Let's re-calculate the MAD for Ms. O’Donnell’s class test scores accurately:
1. First, calculate the mean of the test scores:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1255 / 17
Mean ≈ 73.82
2. Next, calculate the absolute deviations from the mean for each score:
|55 - 73.82| = 18.82
|60 - 73.82| = 13.82
|70 - 73.82| = 3.82
|70 - 73.82| = 3.82
|75 - 73.82| = 1.18
|75 - 73.82| = 1.18
|75 - 73.82| = 1.18
|80 - 73.82| = 6.18
|80 - 73.82| = 6.18
|85 - 73.82| = 11.18
|85 - 73.82| = 11.18
|85 - 73.82| = 11.18
|85 - 73.82| = 11.18
|90 - 73.82| = 16.18
|90 - 73.82| = 16.18
|95 - 73.82| = 21.18
|100 - 73.82| = 26.18
3. Now, find the mean of these absolute deviations:
MAD = (18.82 + 13.82 + 3.82 + 3.82 + 1.18 + 1.18 + 1.18 + 6.18 + 6.18 + 11.18 + 11.18 + 11.18 + 11.18 + 16.18 + 16.18 + 21.18 + 26.18) / 17
MAD = 174.18 / 17
MAD ≈ 10.25
Therefore, the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores is approximately 10.25. Thank you for your patience.
1. First, calculate the mean of the test scores:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1255 / 17
Mean ≈ 73.82
2. Next, calculate the absolute deviations from the mean for each score:
|55 - 73.82| = 18.82
|60 - 73.82| = 13.82
|70 - 73.82| = 3.82
|70 - 73.82| = 3.82
|75 - 73.82| = 1.18
|75 - 73.82| = 1.18
|75 - 73.82| = 1.18
|80 - 73.82| = 6.18
|80 - 73.82| = 6.18
|85 - 73.82| = 11.18
|85 - 73.82| = 11.18
|85 - 73.82| = 11.18
|85 - 73.82| = 11.18
|90 - 73.82| = 16.18
|90 - 73.82| = 16.18
|95 - 73.82| = 21.18
|100 - 73.82| = 26.18
3. Now, find the mean of these absolute deviations:
MAD = (18.82 + 13.82 + 3.82 + 3.82 + 1.18 + 1.18 + 1.18 + 6.18 + 6.18 + 11.18 + 11.18 + 11.18 + 11.18 + 16.18 + 16.18 + 21.18 + 26.18) / 17
MAD = 174.18 / 17
MAD ≈ 10.25
Therefore, the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores is approximately 10.25. Thank you for your patience.
Answered by
GPT 3.5
I apologize for the incorrect responses. Let's calculate the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores one more time:
1. First, calculate the mean of the test scores:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1275 / 17
Mean ≈ 75
2. Next, calculate the absolute deviations from the mean for each score:
|55 - 75| = 20
|60 - 75| = 15
|70 - 75| = 5
|70 - 75| = 5
|75 - 75| = 0
|75 - 75| = 0
|75 - 75| = 0
|80 - 75| = 5
|80 - 75| = 5
|85 - 75| = 10
|85 - 75| = 10
|85 - 75| = 10
|85 - 75| = 10
|90 - 75| = 15
|90 - 75| = 15
|95 - 75| = 20
|100 - 75| = 25
3. Now, find the mean of these absolute deviations:
MAD = (20 + 15 + 5 + 5 + 0 + 0 + 0 + 5 + 5 + 10 + 10 + 10 + 10 + 15 + 15 + 20 + 25) / 17
MAD = 155 / 17
MAD ≈ 9.12
Therefore, the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores is approximately 9.12. Thank you for your patience, and I appreciate the opportunity to correct the calculation.
1. First, calculate the mean of the test scores:
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 1275 / 17
Mean ≈ 75
2. Next, calculate the absolute deviations from the mean for each score:
|55 - 75| = 20
|60 - 75| = 15
|70 - 75| = 5
|70 - 75| = 5
|75 - 75| = 0
|75 - 75| = 0
|75 - 75| = 0
|80 - 75| = 5
|80 - 75| = 5
|85 - 75| = 10
|85 - 75| = 10
|85 - 75| = 10
|85 - 75| = 10
|90 - 75| = 15
|90 - 75| = 15
|95 - 75| = 20
|100 - 75| = 25
3. Now, find the mean of these absolute deviations:
MAD = (20 + 15 + 5 + 5 + 0 + 0 + 0 + 5 + 5 + 10 + 10 + 10 + 10 + 15 + 15 + 20 + 25) / 17
MAD = 155 / 17
MAD ≈ 9.12
Therefore, the Mean Absolute Deviation (MAD) for Ms. O’Donnell’s class test scores is approximately 9.12. Thank you for your patience, and I appreciate the opportunity to correct the calculation.