To find the surface area of the rectangular prism as shown in the net, you first need to calculate the areas of each of the rectangular faces and the two triangular faces (the cones).
Each rectangular face has an area of 8m x 3m = 24m^2. There are three of these faces, so the total area for the rectangular faces is 3 x 24m^2 = 72m^2.
To find the area of a cone, you use the formula A = πr(r + √(r^2 + h^2)), where r is the radius and h is the height. For the left cone, the radius is 2.6m and the height is 3m, so the area is A = π * 2.6(2.6 + √(2.6^2 + 3^2)) = 23.5m^2 (rounded to the nearest tenth). Since there are two cones, the total area for the cones is 2 x 23.5m^2 = 47m^2.
Therefore, the total surface area of the rectangular prism is 72m^2 (rectangular faces) + 47m^2 (cones) = 119m^2.
What is the surface of the rectangular prism shown as a net? Round answer to the nearest tenth. Illustration shows 3 rectangles with a base of 8m and a height each rectangle as 3m. One cone on each end of the middle rectangle. Left is labeled 2.6m with a dotted line through it. The cone on the right is labeled 3m
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