A company that manufacturers wine claims that red wine contains 14.1% by volume of ethanol (density of ethanol is 0.789g/cm³) calculate the molality of ethanol. Molarity of ethanol. % by mass. and ppm and ppb by mass of ethanol

Answer 1

To calculate the molality of ethanol in red wine, we need to first convert the % by volume of ethanol to grams of ethanol per 100g of wine.

14.1% by volume of ethanol means 14.1g of ethanol per 100g of wine.

Next, we need to convert the grams of ethanol to moles. The molar mass of ethanol (C2H5OH) is approximately 46.07 g/mol.

molality = moles of solute / kg of solvent
molarity = moles of solute / liter of solution

molality = (14.1g / 46.07 g/mol) / (100g / 1000)g = 3.0576 mol/kg

molarity = (14.1g / 46.07 g/mol) / (100g / 1000)g = 0.30576 mol/L

% by mass of ethanol = (14.1g / 100g) * 100 = 14.1%

ppm by mass of ethanol = (14.1g / 1000g) * 1000000 = 14100 ppm

ppb by mass of ethanol = (14.1g / 1000000g) * 1000000000 = 14100000 ppb

Therefore, the molality of ethanol in red wine is 3.0576 mol/kg, molarity is 0.30576 mol/L, % by mass is 14.1%, ppm by mass is 14100 ppm, and ppb by mass is 14100000 ppb.