Which of the following is a point on the graft as described by the function y = 2x + 1 ^ 2 - 4

Answer 1

There appears to be a typo in the function provided. The correct function should be y = (2x + 1)^2 - 4.

To find a point on the graph of this function, we can choose a specific value of x and then calculate the corresponding value of y.

For example, if we choose x = 0:

y = (2(0) + 1)^2 - 4
y = (1)^2 - 4
y = 1 - 4
y = -3

Therefore, the point on the graph of the function y = (2x + 1)^2 - 4 at x = 0 is (0, -3).