Question

Solve the system of equations

8X-3y=-22
y=10+4x

Answer 1

Write it as this (__,__)

Answer 2

Solve the systems of equations
5x+2y=14
x-6y=22

Answer 3

Solve the system of equations
-9x+y=12
2x+4y=-28

Answer 4

No decimals

Answer 5

How many solutions does the system of equations have?
6x+2y=-18
3X+y=24

Answer 6

To solve this system of equations, we can substitute the value of y from the second equation into the first equation.

Substitute y = 10 + 4x into the first equation:
8x - 3(10 + 4x) = -22
8x - 30 - 12x = -22
-4x - 30 = -22
-4x = 8
x = -2

Now substitute the value of x back into the second equation to find the value of y:
y = 10 + 4(-2)
y = 10 - 8
y = 2

Therefore, the solution to the system of equations is x = -2 and y = 2.

Answer 7

The solution to the system of equations is (-2, 2).

Answer 8

To solve this system of equations, we can use the method of substitution or elimination. Here, we will use the method of substitution.

First, solve the second equation for x:
x = 22 + 6y

Now, substitute the expression for x into the first equation:
5(22 + 6y) + 2y = 14
110 + 30y + 2y = 14
32y = -96
y = -3

Now, substitute y = -3 back into the second equation to solve for x:
x - 6(-3) = 22
x + 18 = 22
x = 4

Therefore, the solution to the system of equations is x = 4 and y = -3, written as (4, -3).

Answer 9

To solve this system of equations, we can use the method of substitution or elimination. Here, we will use the elimination method.

First, we will multiply the first equation by 4 and the second equation by 1 to create opposite coefficients for y:

-36x + 4y = 48
2x + 4y = -28

Adding the two equations together, we get:

-34x = 20
x = -20/34
x = -10/17

Now, substitute x = -10/17 into the first equation to solve for y:

-9(-10/17) + y = 12
90/17 + y = 12
y = 12 - 90/17
y = (204 - 90) / 17
y = 114 / 17
y = 6.7 (rounded to one decimal place)

Therefore, the solution to the system of equations is x = -10/17 and y = 6.7, written as (-10/17, 6.7) or approximately (-0.59, 6.7).

Answer 10

To solve the system of equations -9x+y=12 and 2x+4y=-28, we can use the elimination method.

First, let's multiply the first equation by 4 to have a 4y term in both equations:

-36x + 4y = 48
2x + 4y = -28

Now, we will subtract the second equation from the first equation to eliminate the y term:

-36x + 4y - 2x - 4y = 48 - (-28)
-38x = 76
x = -76/38
x = -2

Now that we have found the value of x, we can substitute it back into the first equation to solve for y:

-9(-2) + y = 12
18 + y = 12
y = 12 - 18
y = -6

Therefore, the solution to the system of equations is x = -2 and y = -6, written as (-2, -6).

Answer 11

To determine the number of solutions the system of equations has, we can analyze the coefficients of x and y in the equations.

The first equation is 6x + 2y = -18. By dividing the whole equation by 2, we get 3x + y = -9. This equation can be rewritten as 3x + y = -9.

The second equation is 3x + y = 24.

When we compare these two equations, we can see that they represent two parallel lines, as the coefficients of x and y are the same in both equations, but the constants on the right side of the equal sign are different (one is -9, and the other is 24).

Since the equations represent lines that are parallel, they will never intersect, and there is no solution. This system of equations is inconsistent and has 0 solutions.