To find the probability of randomly selecting an employee who eats breakfast or lunch at the office, we need to consider the total number of employees who eat breakfast and/or lunch.
Total number of employees who eat breakfast = 20
Total number of employees who eat lunch = 50
Total number of employees who eat both breakfast and lunch = 15
To avoid counting the employees who eat both breakfast and lunch twice, we need to subtract the number of employees who eat both from the total number of employees who eat breakfast and/or lunch:
Total number of employees who eat breakfast or lunch = Total breakfast eaters + Total lunch eaters - Total employees who eat both breakfast and lunch
Total number of employees who eat breakfast or lunch = 20 + 50 - 15 = 55
Therefore, out of the 80 employees surveyed, 55 eat breakfast or lunch at the office.
The probability of randomly selecting an employee who eats breakfast or lunch at the office is calculated as follows:
Probability = Number of employees who eat breakfast or lunch / Total number of employees surveyed
Probability = 55 / 80
Probability = 0.6875
Therefore, the probability of randomly selecting an employee who eats breakfast or lunch at the office is 0.6875 or 68.75%.
Question 3
A survey of 80 employees was conducted asking about which meals they
regularly eat at the office. Twenty employees eat breakfast at the office, 50
eat lunch, and 15 eat both breakfast and lunch. If an employee is randomly
selected from this group, what is the probability of randomly selecting an
employee who eat breakfast or lunch at the office? Explain how you got the
answer.
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1 answer