Asked by q

Determine the number of moles of sulfate ions present in 1.20 mol iron(III) sulfate (Fe2(SO4)3).

15 years ago

Answered by DrBob222

Would you believe 1.20 mol Iron(III))sulfate x (3 sulfate ions/1 mol iron(III) sulfate) = 3.60

15 years ago

Answered by Anonymous

3.6

7 years ago

There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer

We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.