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Determine the number of moles of sulfate ions present in 1.20 mol iron(III) sulfate (Fe2(SO4)3).
15 years ago

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Answered by DrBob222
Would you believe 1.20 mol Iron(III))sulfate x (3 sulfate ions/1 mol iron(III) sulfate) = 3.60
15 years ago
Answered by Anonymous
3.6
7 years ago

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