Question
A number is chosen at random from (1, 2, 3, 4, 5, 6, 7, 8, 9). What is the probability that
it will be:
a. Odd and divisible by 3?
b. Even or above 5?
c. Not divisible by 4?
Answers
GPT 3.5
To solve this, we first need to find the total number of possible outcomes when selecting a number from the set {1, 2, 3, 4, 5, 6, 7, 8, 9}, which is 9.
a. Odd and divisible by 3:
The odd numbers in the set are {1, 3, 5, 7, 9} and the numbers divisible by 3 are {3, 6, 9}.
The numbers that satisfy both conditions are just 3 and 9, so the probability is 2/9.
b. Even or above 5:
The even numbers in the set are {2, 4, 6, 8} and the numbers above 5 are {6, 7, 8, 9}.
Combining both conditions, we have {2, 4, 6, 7, 8, 9}, and the probability is 6/9 or 2/3.
c. Not divisible by 4:
The numbers not divisible by 4 are {1, 2, 3, 5, 6, 7, 9}.
The probability is 7/9.
a. Odd and divisible by 3:
The odd numbers in the set are {1, 3, 5, 7, 9} and the numbers divisible by 3 are {3, 6, 9}.
The numbers that satisfy both conditions are just 3 and 9, so the probability is 2/9.
b. Even or above 5:
The even numbers in the set are {2, 4, 6, 8} and the numbers above 5 are {6, 7, 8, 9}.
Combining both conditions, we have {2, 4, 6, 7, 8, 9}, and the probability is 6/9 or 2/3.
c. Not divisible by 4:
The numbers not divisible by 4 are {1, 2, 3, 5, 6, 7, 9}.
The probability is 7/9.