To calculate the probability of selecting an apple and a banana, we first find the total number of ways to select 2 fruits out of 20 fruits in the basket.
Total number of ways to select 2 fruits = 20 choose 2 = 20! / (2!(20-2)!) = 190
Next, we find the number of ways to select an apple and a banana. There are 7 apples and 5 bananas in the basket, so the number of ways to select an apple and a banana = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana = Number of ways to select an apple and a banana / Total number of ways to select 2 fruits = 35 / 190 = 7 / 38 ≈ 0.1842
So, the correct answer is Startfraction 7 over 38 End Fraction.
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.(1 point) Responses 776 Startfraction 7 over 76 End Fraction 35 Start Fraction 3 over 5 Endfraction 21190 Startfraction 21 over 190 End Fraction 780
5 answers
r u sure
I apologize for the error in my previous response. Let's correct the calculation.
To calculate the probability of selecting an apple and a banana, we first find the total number of ways to select 2 fruits out of 20 fruits in the basket.
Total number of ways to select 2 fruits = 20 choose 2 = 20! / (2!(20-2)!) = 190
Next, we find the number of ways to select an apple and a banana. There are 7 apples and 5 bananas in the basket, so the number of ways to select an apple and a banana = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana = Number of ways to select an apple and a banana / Total number of ways to select 2 fruits = 35 / 190 = 7 / 38 ≈ 0.1842
So, the correct answer is Startfraction 7 over 38 End Fraction.
To calculate the probability of selecting an apple and a banana, we first find the total number of ways to select 2 fruits out of 20 fruits in the basket.
Total number of ways to select 2 fruits = 20 choose 2 = 20! / (2!(20-2)!) = 190
Next, we find the number of ways to select an apple and a banana. There are 7 apples and 5 bananas in the basket, so the number of ways to select an apple and a banana = 7 * 5 = 35
Therefore, the probability of selecting an apple and a banana = Number of ways to select an apple and a banana / Total number of ways to select 2 fruits = 35 / 190 = 7 / 38 ≈ 0.1842
So, the correct answer is Startfraction 7 over 38 End Fraction.
there is no 7/38
I apologize for the error in my previous responses. Let's recalculate the probability of selecting an apple and a banana:
Total number of fruits in the basket = 5 bananas + 8 mangoes + 7 apples = 20 fruits.
Total number of ways to select 2 fruits out of 20 = 20 choose 2 = 20! / (2!(20-2)!) = 190 ways.
Number of ways to select an apple and a banana = 7 apples * 5 bananas = 35 ways.
So, the probability of selecting an apple and a banana = Number of ways to select an apple and a banana / Total number of ways to select 2 fruits = 35 / 190 ≈ 0.1842.
Therefore, the correct probability of selecting an apple and a banana is approximately 0.1842.
Please let me know if you need any further clarification.
Total number of fruits in the basket = 5 bananas + 8 mangoes + 7 apples = 20 fruits.
Total number of ways to select 2 fruits out of 20 = 20 choose 2 = 20! / (2!(20-2)!) = 190 ways.
Number of ways to select an apple and a banana = 7 apples * 5 bananas = 35 ways.
So, the probability of selecting an apple and a banana = Number of ways to select an apple and a banana / Total number of ways to select 2 fruits = 35 / 190 ≈ 0.1842.
Therefore, the correct probability of selecting an apple and a banana is approximately 0.1842.
Please let me know if you need any further clarification.
1 answer