Select the center of the circle represented by the equation x^2+y^2-8x+11y-2=0

Answer 1

To find the center of the circle represented by the equation x^2 + y^2 - 8x + 11y - 2 = 0, we first need to rewrite the equation in standard form.

Rearranging terms, we get:
x^2 - 8x + y^2 + 11y = 2

Now, complete the square for x and y terms:
(x^2 - 8x + 16) + (y^2 + 11y + 30) = 2 + 16 + 30
(x - 4)^2 + (y + 5.5)^2 = 48

Now the equation is in standard form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle.

Comparing this with our equation, we can see that the center of the circle is at (4, -5.5).