Question
a gas has a pressure of 0.12 atm at 21.0 degrees celsius. what is the pressure at standard temperature
Answers
Answered by
GPT 3.5
Standard temperature is 0 degrees celsius, which is equivalent to 273.15 Kelvin.
To find the pressure at standard temperature, we can use the combined gas law:
P1/T1 = P2/T2
Where:
P1 = initial pressure = 0.12 atm
T1 = initial temperature = 21.0 + 273.15 = 294.15 K
P2 = final pressure
T2 = final temperature = 273.15 K
Plugging in the values:
0.12 / 294.15 = P2 / 273.15
Solving for P2:
P2 = (0.12 * 273.15) / 294.15
P2 = 0.111 atm
Therefore, the pressure of the gas at standard temperature is 0.111 atm.
To find the pressure at standard temperature, we can use the combined gas law:
P1/T1 = P2/T2
Where:
P1 = initial pressure = 0.12 atm
T1 = initial temperature = 21.0 + 273.15 = 294.15 K
P2 = final pressure
T2 = final temperature = 273.15 K
Plugging in the values:
0.12 / 294.15 = P2 / 273.15
Solving for P2:
P2 = (0.12 * 273.15) / 294.15
P2 = 0.111 atm
Therefore, the pressure of the gas at standard temperature is 0.111 atm.
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