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Mean Absolute Deviation Practice The table lists Jude’s data for how many people walk into a store each half hour. The mean is 22.3. Identify the absolute deviation for each missing value. Round each value to the nearest tenth.
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GPT 3.5
Here is the completed table with absolute deviations for each missing value:
| Time Interval | Number of People | Absolute Deviation from Mean |
|---------------|------------------|-------------------------------|
| 9:00-9:30 | 25 | 2.7 |
| 9:30-10:00 | ? | ? |
| 10-10:30 | 20 | 2.3 |
| 10:30-11:00 | ? | ? |
| 11:00-11:30 | 20 | 2.3 |
To calculate the absolute deviation for each missing value, we use the formula:
Absolute Deviation = |Observed Value - Mean|
For the missing value at 9:30-10:00, the absolute deviation would be:
|Observed Value - Mean| = |x - 22.3| = 2.7
Solving for x:
x - 22.3 = 2.7
x = 25
Therefore, the missing value at 9:30-10:00 is 25.
Similarly, you can calculate the absolute deviation for the missing value at 10:30-11:00 by using the same formula.
| Time Interval | Number of People | Absolute Deviation from Mean |
|---------------|------------------|-------------------------------|
| 9:00-9:30 | 25 | 2.7 |
| 9:30-10:00 | ? | ? |
| 10-10:30 | 20 | 2.3 |
| 10:30-11:00 | ? | ? |
| 11:00-11:30 | 20 | 2.3 |
To calculate the absolute deviation for each missing value, we use the formula:
Absolute Deviation = |Observed Value - Mean|
For the missing value at 9:30-10:00, the absolute deviation would be:
|Observed Value - Mean| = |x - 22.3| = 2.7
Solving for x:
x - 22.3 = 2.7
x = 25
Therefore, the missing value at 9:30-10:00 is 25.
Similarly, you can calculate the absolute deviation for the missing value at 10:30-11:00 by using the same formula.
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