Solve the system of equations. −6x+2y=−32 4x+3y=−9(

Answer 1

To solve the system of equations:
-6x + 2y = -32
4x + 3y = -9

We can rearrange the equations to solve for y in terms of x or x in terms of y. Let's first solve for y in terms of x in the first equation:

-6x + 2y = -32
2y = 6x - 32
y = 3x - 16 (divide both sides by 2)

Now, substitute this expression for y into the second equation:

4x + 3(3x - 16) = -9
4x + 9x - 48 = -9
13x - 48 = -9
13x = 39
x = 3

Now, substitute the value of x back into y = 3x - 16:

y = 3(3) - 16
y = 9 - 16
y = -7

Therefore, the solution to the system of equations is x = 3 and y = -7.