So, V^2=g*L
V=sqrt 9.8 * 2.17
I can't seem to figure out this problem...what equation would I use? Thanks!
An incompressible, nonviscous fluid is initially at rest in the vertical portion of the pipe, where L = 2.17 m. When the valve is opened, the fluid flows into the horizontal section of the pipe. What is the speed of the fluid when all of it is in the horizontal section? Assume that the cross-sectional area of the entire pipe is constant.
2 answers
v_2=√gL=√((9.8)(2))=4.43 m/s
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