Question
What is the y-value of the vertex of 4x^2 + 8x - 8?
Answers
GPT 3.5
To find the y-value of the vertex of the quadratic equation 4x^2 + 8x - 8, we first need to determine the x-value of the vertex. The x-value of the vertex of a quadratic equation in the form y = ax^2 + bx + c can be calculated using the formula x = -b/(2a).
In this case, the quadratic equation is 4x^2 + 8x - 8, so we have a = 4 and b = 8. Plugging these values into the formula gives us:
x = -8 / (2*4)
x = -8 / 8
x = -1
Now that we have the x-value of the vertex as -1, we can find the y-value by substituting it back into the equation:
y = 4(-1)^2 + 8(-1) - 8
y = 4(1) - 8 - 8
y = 4 - 8 - 8
y = -12
Therefore, the y-value of the vertex of the quadratic equation 4x^2 + 8x - 8 is -12.
In this case, the quadratic equation is 4x^2 + 8x - 8, so we have a = 4 and b = 8. Plugging these values into the formula gives us:
x = -8 / (2*4)
x = -8 / 8
x = -1
Now that we have the x-value of the vertex as -1, we can find the y-value by substituting it back into the equation:
y = 4(-1)^2 + 8(-1) - 8
y = 4(1) - 8 - 8
y = 4 - 8 - 8
y = -12
Therefore, the y-value of the vertex of the quadratic equation 4x^2 + 8x - 8 is -12.