The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
Given the point (10, 9) and a slope of 5/2, we can substitute these values into the equation to solve for b:
9 = (5/2)(10) + b
9 = 25 + b
b = -16
Therefore, the equation of the line passing through the point (10, 9) with a slope of 5/2 is:
y = (5/2)x - 16
A line passes through the point (10, 9) and has a slope of 5/2.
Write an equation in slope-intercept form for this line.
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