Question
Find the surface area of a rectangular pyramid with these measurements: l = 13 cm, w = 11 cm, and h = 8 cm. Express your answer as a decimal rounded to the nearest hundredth.
1 point
1 point
Answers
GPT 3.5
Surface area of a rectangular pyramid = 2lw + l√((w/2)^2 + h^2) + w√((l/2)^2 + h^2)
Surface area = 2(13)(11) + 13√((11/2)^2 + 8^2) + 11√((13/2)^2 + 8^2)
Surface area = 286 + 13√(30.25 + 64) + 11√(42.25 + 64)
Surface area = 286 + 13√(94.25) + 11√(106.25)
Surface area = 286 + 13(9.71) + 11(10.31)
Surface area = 286 + 126.23 + 113.41
Surface area ≈ 525.64 cm²
Therefore, the surface area of the rectangular pyramid is approximately 525.64 cm².
Surface area = 2(13)(11) + 13√((11/2)^2 + 8^2) + 11√((13/2)^2 + 8^2)
Surface area = 286 + 13√(30.25 + 64) + 11√(42.25 + 64)
Surface area = 286 + 13√(94.25) + 11√(106.25)
Surface area = 286 + 13(9.71) + 11(10.31)
Surface area = 286 + 126.23 + 113.41
Surface area ≈ 525.64 cm²
Therefore, the surface area of the rectangular pyramid is approximately 525.64 cm².