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The average temperatures in December in Washington, D.C., from 1993 to 1998 are given as a dataset. 38.1, 44.2, 35.6, 43.0, 41....Question
The average temperatures in December in Washington, D.C., from 1993 to 1998 are given as a dataset.
38.1, 44.2, 35.6, 43.0, 41.0, 44.4
Find the interquartile range of the dataset.
(1 point)
The interquartile range of the dataset is
.
38.1, 44.2, 35.6, 43.0, 41.0, 44.4
Find the interquartile range of the dataset.
(1 point)
The interquartile range of the dataset is
.
Answers
Answered by
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Answered by
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7.4.
To find the interquartile range, we first need to find the first quartile (Q1) and the third quartile (Q3).
1. First, we need to arrange the data in ascending order:
35.6, 38.1, 41.0, 43.0, 44.2, 44.4
2. Next, find the median of the dataset. Since the dataset has an even number of values, the median is the average of the two middle values:
(41.0 + 43.0) / 2 = 42.0
3. Now, we divide the dataset into two halves.
- For the lower half: 35.6, 38.1, 41.0
- For the upper half: 43.0, 44.2, 44.4
4. Next, find the median of each half.
- Q1 = (38.1 + 41.0) / 2 = 39.55
- Q3 = (43.0 + 44.2) / 2 = 43.6
5. Finally, calculate the interquartile range by subtracting Q1 from Q3:
43.6 - 39.55 = 4.05
Therefore, the interquartile range of the dataset is 4.05.
To find the interquartile range, we first need to find the first quartile (Q1) and the third quartile (Q3).
1. First, we need to arrange the data in ascending order:
35.6, 38.1, 41.0, 43.0, 44.2, 44.4
2. Next, find the median of the dataset. Since the dataset has an even number of values, the median is the average of the two middle values:
(41.0 + 43.0) / 2 = 42.0
3. Now, we divide the dataset into two halves.
- For the lower half: 35.6, 38.1, 41.0
- For the upper half: 43.0, 44.2, 44.4
4. Next, find the median of each half.
- Q1 = (38.1 + 41.0) / 2 = 39.55
- Q3 = (43.0 + 44.2) / 2 = 43.6
5. Finally, calculate the interquartile range by subtracting Q1 from Q3:
43.6 - 39.55 = 4.05
Therefore, the interquartile range of the dataset is 4.05.
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