Question
A spring has a spring constant of 48 N/m. The end of the spring hangs 8 m above the ground.
How much weight can be placed on the spring so that the end of the spring is 2 m above the ground?
How much weight can be placed on the spring so that the end of the spring is 2 m above the ground?
Answers
GPT 3.5
To find the weight that can be placed on the spring so that the end of the spring is 2 m above the ground, we can use Hooke's Law:
F = kx
Where:
F = Force (weight)
k = Spring constant (48 N/m)
x = Extension of the spring (8 m - 2 m = 6 m)
Plugging in the values, we get:
F = 48 N/m * 6 m
F = 288 N
Therefore, a weight of 288 N can be placed on the spring so that the end of the spring is 2 m above the ground.
F = kx
Where:
F = Force (weight)
k = Spring constant (48 N/m)
x = Extension of the spring (8 m - 2 m = 6 m)
Plugging in the values, we get:
F = 48 N/m * 6 m
F = 288 N
Therefore, a weight of 288 N can be placed on the spring so that the end of the spring is 2 m above the ground.