Question

The stem-and-leaf plot shows the ages of a group of friends. Find the median age.
Stem Leaf
2 8
3 1 2 4
4 2 7 9
5 4
Key: 2|8=28 years

Answer 1

Here are the math test scores of 10 randomly selected students from Class 1 and Class 2.
Class 1: 75 80 84 79 92 86 88 86 86 90
Class 2: 83 85 91 93 72 85 76 80 82 89
Find the mean score of each sample. Based on the mean, which class generally performed better on the math test?

Answer 2

wrong class 1 is not 85.6 and class 2 isn't 84.6

Answer 3

wrong here is the Question again
Here are the math test scores of 10 randomly selected students from Class 1 and Class 2. Class 1: 75 80 84 79 92 86 88 86 86 90 Class 2: 83 85 91 93 72 85 76 80 82 89 Find the mean score of each sample. Based on the mean, which class generally performed better on the math test? (2 points) The mean score for Class 1 is __. The mean score for Class 2 is __. Based on the mean, Class 1 generally performed better on the math test.

Answer 4

its still wrong bot can you try again?

Answer 5

To find the median age, we first need to arrange the ages in numerical order:

28, 31, 32, 34, 42, 47, 49, 54

There are a total of 8 ages, so the median will be the average of the 4th and 5th ages when arranged in order. The 4th and 5th ages are 34 and 42.

Therefore, the median age of the group of friends is:

(34 + 42) / 2 = 38

Answer 6

To find the mean score for each class, we first need to calculate the sum of the scores in each class and then divide by the number of students in each class.

For Class 1:
Sum of scores = 75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90 = 856
Number of students = 10
Mean score for Class 1 = 856 / 10 = 85.6

For Class 2:
Sum of scores = 83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89 = 846
Number of students = 10
Mean score for Class 2 = 846 / 10 = 84.6

Therefore, Class 1 generally performed better on the math test as it has a higher mean score of 85.6 compared to Class 2's mean score of 84.6.

Answer 7

Let's recalculate the mean scores for each class.

For Class 1:
Sum of scores = 75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90 = 860
Number of students = 10
Mean score for Class 1 = 860 / 10 = 86

For Class 2:
Sum of scores = 83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89 = 846
Number of students = 10
Mean score for Class 2 = 846 / 10 = 84.6

Therefore, based on the new calculations, Class 1 had a mean score of 86 while Class 2 had a mean score of 84.6. This means that Class 1 generally performed better on the math test compared to Class 2.

Answer 8

Let's recalculate the mean scores for each class:

For Class 1:
Sum of scores = 75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90 = 850
Number of students = 10
Mean score for Class 1 = 850 / 10 = 85

For Class 2:
Sum of scores = 83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89 = 846
Number of students = 10
Mean score for Class 2 = 846 / 10 = 84.6

Therefore, the mean score for Class 1 is 85 and the mean score for Class 2 is 84.6. Based on the mean scores, Class 1 generally performed better on the math test.

Answer 9

My apologies for the mistake. Let's recalculate the mean scores for each class:

For Class 1:
Sum of scores = 75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90 = 850
Number of students = 10
Mean score for Class 1 = 850 / 10 = 85

For Class 2:
Sum of scores = 83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89 = 846
Number of students = 10
Mean score for Class 2 = 846 / 10 = 84.6

Therefore, the mean score for Class 1 is 85 and the mean score for Class 2 is 84.6. Based on the mean scores, Class 1 generally performed better on the math test.