Asked by Mischell Paul
In a chemical reaction,4 mol of nitrogen monoxide(NO) and 2.5mol of Oxygen(O2) are being mixed togethere in a container with a volume of 1L to produce Nitrogen dioxide (NO2).If the Kc(Equilibrium constant) for this reaction in 0.001.
If the enthalpy of the above reaction is +49kJ/mol. Predict the outcome of the reaction
If the enthalpy of the above reaction is +49kJ/mol. Predict the outcome of the reaction
Answers
Answered by
GPT 3.5
To predict the outcome of the reaction, we need to compare the reaction quotient (Q) with the equilibrium constant (Kc).
The balanced chemical equation for the reaction is:
2NO (g) + O2 (g) -> 2NO2 (g)
The reaction quotient (Q) is calculated by taking the products raised to their coefficients and dividing by the reactants raised to their coefficients:
Q = [NO2]^2 / [NO]^2 [O2]
Given that the initial moles of NO and O2 are 4 mol and 2.5 mol respectively, the initial moles of NO2 would be 0 mol.
Therefore, Q = (0/4)^2 / (4/1)^2 (2.5/1) = 0
Since Q < Kc, the reaction will proceed in the forward direction to reach equilibrium. Therefore, the reaction will proceed to form more NO2 until it reaches equilibrium.
The balanced chemical equation for the reaction is:
2NO (g) + O2 (g) -> 2NO2 (g)
The reaction quotient (Q) is calculated by taking the products raised to their coefficients and dividing by the reactants raised to their coefficients:
Q = [NO2]^2 / [NO]^2 [O2]
Given that the initial moles of NO and O2 are 4 mol and 2.5 mol respectively, the initial moles of NO2 would be 0 mol.
Therefore, Q = (0/4)^2 / (4/1)^2 (2.5/1) = 0
Since Q < Kc, the reaction will proceed in the forward direction to reach equilibrium. Therefore, the reaction will proceed to form more NO2 until it reaches equilibrium.
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