To find the minimum value of the parabola y = x^2 - 3x, we first need to determine the x-coordinate of the vertex of the parabola. The x-coordinate of the vertex of the parabola y = ax^2 + bx + c is given by the formula x = -b/2a.
In this case, a = 1, b = -3, and c = 0. Plugging these values into the formula, we get x = -(-3) / 2(1) = 3/2 = 1.5.
Now that we have the x-coordinate of the vertex, we can find the y-coordinate by substituting x = 1.5 into the equation y = x^2 - 3x.
y = (1.5)^2 - 3(1.5)
y = 2.25 - 4.5
y = -2.25
Therefore, the minimum value of the parabola y = x^2 - 3x is -2.25.
Find the minimum valueof the parabola y = x2 − 3x.
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