To find the new ordered pair of point N′ after the dilation, we need to multiply the original coordinates of point N by the scale factor of 2/5.
Point N: (-6, 2)
Scale factor: 2/5
New x-coordinate of N′: -6 * 2/5 = -12/5 = -2.4
New y-coordinate of N′: 2 * 2/5 = 4/5 = 0.8
Therefore, the ordered pair of point N′ is (-2.4, 0.8), which corresponds to the answer choice (-2.4, 0.8).
Hexagon IJKLMN is shown on the coordinate plane below:
hexagon IJKLMN on a coordinate plane with ordered pairs at I negative two, six, at J four, four, at K six, negative one, at L negative one, two, at M negative four, negative four, and at N negative six, two
If hexagon IJKLMN is dilated by a scale factor of two fifths from the origin to create hexagon I′J′K′L′M′N′, what is the ordered pair of point N′?
(−0.4, 0.8)
(−0.8, 2.4)
(−2.4, 0.8)
(−15, 5)
1 answer
1 answer