Asked by Rmz
An experiment has three possible outcomes: A, B, and C. If P(A)= P(B)and P(C)= 2P(A), what is the probability of each?
Can anyone help me get started?
Can anyone help me get started?
Answers
Answered by
Marth
Consider that P(A) + P(B) + P(C) = 1.
Answered by
Rmz
What do you mean?
Answered by
Marth
The sum of the probabilities of each outcome must equal 1. Therefore, you can find the probability of any outcome by algebra.
P(A) + P(B) + P(C) = 1
I'll start you off.
Let x = P(A).
"P(A)= P(B)and P(C)= 2P(A)"
Then x = P(B) and 2x = P(C).
x + x + 2x = 1
P(A) + P(B) + P(C) = 1
I'll start you off.
Let x = P(A).
"P(A)= P(B)and P(C)= 2P(A)"
Then x = P(B) and 2x = P(C).
x + x + 2x = 1
Answered by
Rmz
So say I got x=1/4 would I substitute it in for P(A through C)?
Answered by
Marth
Yes. x = 1/4, so P(A) = x = 1/4. Similarly, you can find P(B) and P(C).
Answered by
Rmz
Alright I think I got it
P(A)= 1/4
P(B)= 2/5
P(C)= 5/14
RIght?
P(A)= 1/4
P(B)= 2/5
P(C)= 5/14
RIght?
Answered by
bobpursley
Really good work.
Answered by
Marth
"P(A)= P(B)and P(C)= 2P(A)"
We found that P(A) = x = 1/4. Therefore, P(B) = P(A) = x = 1/4.
P(C) = 2P(A) = 2x = 1/2
You can see that P(A) + P(B) + P(C) = 1/4 + 1/4 + 1/2 = 1
We found that P(A) = x = 1/4. Therefore, P(B) = P(A) = x = 1/4.
P(C) = 2P(A) = 2x = 1/2
You can see that P(A) + P(B) + P(C) = 1/4 + 1/4 + 1/2 = 1