Rectangle ABCD has vertices point A (−5, 1), point B (-2, 1), point

Question

C (-2, 6), and point D (−5, 6). Find the perimeter of the rectangle in feet.
(1 point)

Answer 1

To find the perimeter of the rectangle, we need to add the lengths of all four sides.

Using the distance formula: d = √[(x2 - x1)^2 + (y2 - y1)^2]

Side AB: √[(-2 - (-5))^2 + (1 - 1)^2] = √[3^2 + 0^2] = √9 = 3
Side BC: √[(-2 - (-2))^2 + (6 - 1)^2] = √[0^2 + 5^2] = √25 = 5
Side CD: √[(-5 - (-2))^2 + (6 - 6)^2] = √[3^2 + 0^2] = √9 = 3
Side DA: √[(-5 - (-5))^2 + (1 - 6)^2] = √[0^2 + (-5)^2] = √25 = 5

Adding the lengths of all four sides:
Perimeter = AB + BC + CD + DA = 3 + 5 + 3 + 5 = 16

Therefore, the perimeter of the rectangle is 16 feet.