The position of the end of the second hand can be described by the equation:
y = h + L sin(ωt)
where:
y = vertical position of the end of the second hand
h = height of the center of the clock on the wall (2m)
L = length of the second hand (4cm = 0.04m)
ω = angular velocity of the second hand (in this case, it completes one full turn every 60 seconds, so ω = 2π/60 = π/30)
t = time in seconds
Substitute the given values into the equation:
y = 2 + 0.04 sin((π/30)t)
Thus, the equation to describe the situation is:
y = 2 + 0.04 sin((π/30)t)
For the motion of the end of the second hand on a clock that is 4cm long and the centre is 2m up on a wall where t=1 is 1 second.Determine an equation to describe the situation ( use sin or cos)
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