Question

1.40 moles of O2 gas is at a pressure 4.00 kPa and at a temperature of 56.0°C. What is the volume of the gas?
*Make sure to always round to the correct number of sig figs
O 77.2 L
O 764 L
O 9.45 L
O 957 L

Answer 1

To find the volume of the gas, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (4.00 kPa)
V = volume
n = moles of gas (1.40 moles)
R = gas constant (8.31 L∙kPa/(K∙mol) )
T = temperature (56.0°C + 273.15 = 329.15 K)

Plugging in the values into the ideal gas law equation:

(4.00 kPa) * V = (1.40 moles) * (8.31 L∙kPa/(K∙mol)) * (329.15 K)

4.00V = 3681.168

V = 3681.168 / 4.00
V = 920.29

Rounded to the correct number of sig figs, the volume of the gas is approximately 920 L.

Therefore, the closest answer is:
O 957 L