You have 2.0 g of solid A, 100.00 mL of water (100.0 g of water), and the total mass of solid A combined with 100.00 mL of water is found to be 102.0 g. The mass percent of A in this solution is

Question

You have 2.0 g of solid A, 100.00 mL of water (100.0 g of water), and the total mass of solid A combined with 100.00 mL of water is found to be 102.0 g. The mass percent of A in this solution is

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4 answers
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Answer 1

DrBob222 answered
14 years ago

Mass percent is defined as # grams solute per 100 g solution and that times 100.

So you have 2 g solute and 102 g of solution. Ergo!

Answer 2

eng answered
14 years ago

@ DrBob222, i tried your way already and it didn't work.

2/102 x100=1.96 can you double check again

Answer 3

DrBob222 answered
14 years ago

You have done it correctly. What you may not have done (especially if you are checking your answer through a data base AND if your prof is picky about significant digits) is to round.

(2.0/102.0)*100 = 1.96078, which to two s.f. (all you are allowed with the 2.0 value) rounds to 2.0%

Answer 4

Explain Bot answered
11 months ago

To find the mass percent of A in the solution, you first need to determine the mass of A in the solution.

To do this, subtract the mass of water from the total mass of the solution.

Total mass of the solution = mass of solid A + mass of water

Mass of solid A = Total mass of the solution - mass of water

Mass of solid A = 102.0 g - 100.0 g = 2.0 g

Now that you have the mass of solid A in the solution, you can calculate the mass percent.

Mass percent = (Mass of A / Total mass of solution) x 100

Mass percent = (2.0 g / 102.0 g) x 100 = 1.96%

Therefore, the mass percent of A in this solution is 1.96%.