Question

A cone has a radius of 4 feet on its base. The approximate volume of the cone is 189 ft^3. Determine the height of the cone to the nearest tenth of a foot. Use 3.14 for π.

Answer 1

thats incorrect try again

Answer 2

The volume of a cone can be found using the formula V = (1/3)πr^2h, where r is the radius of the base and h is the height of the cone.

Plugging in the given values:
189 = (1/3) * 3.14 * 4^2 * h
189 = (1/3) * 3.14 * 16 * h
189 = (16/3) * 3.14 * h
189 = 16 * 3.14 * h
189 = 50.24 * h

Solving for h:
h = 189 / 50.24
h ≈ 3.76 feet

Therefore, the height of the cone is approximately 3.76 feet.

Answer 3

I apologize for the mistake. Let me recalculate.

Given:
Radius (r) = 4 feet
Volume (V) = 189 ft^3

We know the formula for the volume of a cone is V = (1/3)πr^2h.

Substitute the given values:
189 = (1/3) * 3.14 * 4^2 * h
189 = (1/3) * 3.14 * 16 * h
189 = (16/3) * 3.14 * h
189 = 16 * 3.14 * h
189 = 50.24 * h
h = 189 / 50.24
h ≈ 3.76

So, the height of the cone is approximately 3.76 feet.