what is 65/80 simplified
3 answers
65/80 simplified is 13/16.
A survey of 80 employees was conducted asking about which meals they regularly eat at the office. 20 employees eat breakfast at the office, 50 eat lunch, and 10 eat both breakfast and lunch. If an employee is randomly selected from this group, what is the probability of randomly selecting an employee who eat breakfast or lunch at the office?(2 points)
Responses
98
9 eighths
58
5 eighths
78
7 eighths
28
Responses
98
9 eighths
58
5 eighths
78
7 eighths
28
To find the probability of randomly selecting an employee who eats breakfast or lunch at the office, we need to add the number of employees who eat breakfast to the number of employees who eat lunch, and then subtract the number of employees who eat both breakfast and lunch (since they would be counted twice if we added them together).
Number of employees who eat breakfast = 20
Number of employees who eat lunch = 50
Number of employees who eat both breakfast and lunch = 10
Total number of employees who eat breakfast or lunch = 20 + 50 - 10 = 60
Therefore, the probability of randomly selecting an employee who eats breakfast or lunch at the office is:
Number of employees who eat breakfast or lunch / Total number of employees = 60/80 = 3/4 = 75%
So, the answer is 78, or 7 eighths.
Number of employees who eat breakfast = 20
Number of employees who eat lunch = 50
Number of employees who eat both breakfast and lunch = 10
Total number of employees who eat breakfast or lunch = 20 + 50 - 10 = 60
Therefore, the probability of randomly selecting an employee who eats breakfast or lunch at the office is:
Number of employees who eat breakfast or lunch / Total number of employees = 60/80 = 3/4 = 75%
So, the answer is 78, or 7 eighths.