To find the best estimate for the value of f in the table, we need to substitute the x-value from the table into the equation for the line of best fit.
Looking at the table, the x-values are the weeks (0, 1, 2, 3, 4, 5, 6) and the y-values are the number of frogs in the pond at that week.
Let's substitute the x-values into the equation and calculate the corresponding y-values:
- For x = 0, y = 5.82*0 + 0.42 = 0.42
- For x = 1, y = 5.82*1 + 0.42 = 6.24
- For x = 2, y = 5.82*2 + 0.42 = 12.06
- For x = 3, y = 5.82*3 + 0.42 = 17.88
- For x = 4, y = 5.82*4 + 0.42 = 23.70
- For x = 5, y = 5.82*5 + 0.42 = 29.52
- For x = 6, y = 5.82*6 + 0.42 = 35.34
Comparing the calculated y-values with the values in the table, the best estimate for the value of f in the table is 35.
Troy was studying the number of frogs in a pond each week and recorded the data in the table. The equation for the line of best fit is
y=5.82x+0.42
Based on the equation, what is the best estimate for the value of f in the table?
65
68
70
74
None of these
1 answer
8 answers