Asked by Hellen Nathy
if 4.55 g of sodium sulphide and 15.0 g of bismuth nitrate are dissolved in separate beakers of water which are then poured togehter, what is the maximum mass of bismuth sulphide an insoulble compound that could precipitate? Which reactant was the limitting reactant?
Na2S + Bi(NO3)3 --- Bi2S3 + Na^+ + NP3^- ( not balanced )
Na2S + Bi(NO3)3 --- Bi2S3 + Na^+ + NP3^- ( not balanced )
Answers
Answered by
bobpursley
according to the balanced equation, for each one mole of Na2S one mole ofBi(NO3)3 is needed.
So how many moles of each do you start with? The lower number will be the limiting reactant. THis number will also be the number of moles of Bi2S3 produced, convert that to grams.
So how many moles of each do you start with? The lower number will be the limiting reactant. THis number will also be the number of moles of Bi2S3 produced, convert that to grams.
Answered by
Chem
i m getting 9.77 g for Bi2S3 .
no limiting reactant .. both are same ..
can u plz conform
no limiting reactant .. both are same ..
can u plz conform
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