Question

How does h(t)=
2
4t
change over the interval from t=
–
4 to t=5?

Answer 1

To determine how the function h(t) = 2 / 4t changes over the interval from t = -4 to t = 5, we need to calculate the values of h(t) at both t = -4 and t = 5, and then compare them.

First, let's calculate h(-4):
h(-4) = 2 / (4*(-4))
h(-4) = 2 / -16
h(-4) = -1/8

Next, let's calculate h(5):
h(5) = 2 / (4*5)
h(5) = 2 / 20
h(5) = 1/10

Finally, we compare the values:
Since h(-4) = -1/8 is less than h(5) = 1/10, we can conclude that the function h(t) = 2 / 4t increases over the interval from t = -4 to t = 5.

Answer 2

does it increase by 4^9 decrease by 4^9 decrease by 4% or decrease by a factor of 4^9

Answer 3

To determine how the function h(t) = 2 / 4t changes over the interval from t = -4 to t = 5, we can calculate the ratio of h(5) compared to h(-4) to see if it either increases or decreases that much within the interval.

h(-4) = -1/8
h(5) = 1/10

The ratio of h(5) to h(-4) is:
(1/10) / (-1/8) = -8/10 = -0.8

So, the function h(t) changes by a factor of -0.8 within the interval from t = -4 to t = 5. This means it decreases by a factor of 0.8.