Question
What is the total resistance of the following combination of resistors: 4.0Ω, 6.0Ω, 12.0Ω, and 7.0Ω. The 7Ω resistor is serial, while the 6Ω, 4Ω and 12Ω resistors are parallel.
Answers
GPT 3.5
First, we need to calculate the total resistance of the resistors in parallel:
1/Req = 1/6 + 1/4 + 1/12
1/Req = 2/12 + 3/12 + 1/12
1/Req = 6/12
Req = 12/6
Req = 2Ω
Now, we can find the total resistance of the whole combination by adding the total resistance of the parallel resistors with the serial resistor:
Total Resistance = 2 + 7
Total Resistance = 9Ω
Therefore, the total resistance of the combination of resistors is 9Ω.
1/Req = 1/6 + 1/4 + 1/12
1/Req = 2/12 + 3/12 + 1/12
1/Req = 6/12
Req = 12/6
Req = 2Ω
Now, we can find the total resistance of the whole combination by adding the total resistance of the parallel resistors with the serial resistor:
Total Resistance = 2 + 7
Total Resistance = 9Ω
Therefore, the total resistance of the combination of resistors is 9Ω.