Since both equations are set equal to y, we can set them equal to each other to solve for x.
x^2 + 2x = 3x + 20
x^2 - x - 20 = 0
Now we will factor the quadratic equation:
(x - 5)(x + 4) = 0
Setting each factor equal to zero:
x - 5 = 0 or x + 4 = 0
Solving for x in each case:
x = 5 or x = -4
Now that we have found the values of x, we can substitute them back into one of the original equations to solve for y. Let's use the first equation:
y = (5)^2 + 2(5)
y = 25 + 10
y = 35
Therefore, the solution to the system of equations is x = 5 and y = 35, or x = -4 and y = -8.
Solve the system of equations algebraically. simply Show all of your steps.
y = x^2 + 2x
y = 3x + 20
1 answer