A person breathes 2.60 L of air at -11.0 °C into her lungs, where it is warmed to 37.0 °C. What is its new volume?

Answer 1

To solve this problem, we can use the combined gas law formula:

P1V1/T1 = P2V2/T2

Where:
P1 = pressure of the gas initially
V1 = volume of the gas initially
T1 = temperature of the gas initially
P2 = pressure of the gas after change
V2 = volume of the gas after change
T2 = temperature of the gas after change

Since the question only asks for the new volume, we can simplify the formula to:

V2 = (V1 * T2) / T1

First, we need to convert the temperatures from Celsius to Kelvin:
-11.0 °C = 262.15 K (initial temperature)
37.0 °C = 310.15 K (final temperature)

Now we can plug in the values:
V2 = (2.60 L * 310.15 K) / 262.15 K
V2 = 3.08 L

Therefore, the new volume of the air in the lungs after being warmed to 37.0 °C is 3.08 L.